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71748001110131 is a prime number
BaseRepresentation
bin10000010100000100100010…
…000111101001100001110011
3100102001001010120002122020022
4100110010202013221201303
533401004401241011011
6412332324321434055
721053423231642063
oct2024044207514163
9312031116078208
1071748001110131
112095217a184165
1280692b049b92b
133105a66033208
1413a089c2573a3
158464e44658db
hex4141221e9873

71748001110131 has 2 divisors, whose sum is σ = 71748001110132. Its totient is φ = 71748001110130.

The previous prime is 71748001109969. The next prime is 71748001110133. The reversal of 71748001110131 is 13101110084717.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-71748001110131 is a prime.

It is a super-2 number, since 2×717480011101312 (a number of 29 digits) contains 22 as substring.

Together with 71748001110133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 71748001110091 and 71748001110100.

It is not a weakly prime, because it can be changed into another prime (71748001110133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35874000555065 + 35874000555066.

It is an arithmetic number, because the mean of its divisors is an integer number (35874000555066).

Almost surely, 271748001110131 is an apocalyptic number.

71748001110131 is a deficient number, since it is larger than the sum of its proper divisors (1).

71748001110131 is an equidigital number, since it uses as much as digits as its factorization.

71748001110131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4704, while the sum is 35.

Adding to 71748001110131 its reverse (13101110084717), we get a palindrome (84849111194848).

The spelling of 71748001110131 in words is "seventy-one trillion, seven hundred forty-eight billion, one million, one hundred ten thousand, one hundred thirty-one".