718951401401 has 2 divisors, whose sum is σ = 718951401402. Its totient is φ = 718951401400.

The previous prime is 718951401313. The next prime is 718951401403. The reversal of 718951401401 is 104104159817.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 664616257600 + 54335143801 = 815240^2 + 233099^2 .

It is a cyclic number.

It is not a de Polignac number, because 718951401401 - 2¹⁴ = 718951385017 is a prime.

It is a super-5 number, since 5×718951401401⁵ (a number of 60 digits) contains 55555 as substring. Note that it is a super-d number also for d = 2.

Together with 718951401403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (718951401403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 359475700700 + 359475700701.

It is an arithmetic number, because the mean of its divisors is an integer number (359475700701).

Almost surely, 2^718951401401 is an apocalyptic number.

It is an amenable number.

718951401401 is a deficient number, since it is larger than the sum of its proper divisors (1).

718951401401 is an equidigital number, since it uses as much as digits as its factorization.

718951401401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40320, while the sum is 41.

The spelling of 718951401401 in words is "seven hundred eighteen billion, nine hundred fifty-one million, four hundred one thousand, four hundred one".