718951401403 has 2 divisors, whose sum is σ = 718951401404. Its totient is φ = 718951401402.

The previous prime is 718951401401. The next prime is 718951401491. The reversal of 718951401403 is 304104159817.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 718951401403 - 2¹ = 718951401401 is a prime.

It is a super-2 number, since 2×718951401403² (a number of 25 digits) contains 22 as substring.

Together with 718951401401, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 718951401403.

It is not a weakly prime, because it can be changed into another prime (718951401401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 359475700701 + 359475700702.

It is an arithmetic number, because the mean of its divisors is an integer number (359475700702).

Almost surely, 2^718951401403 is an apocalyptic number.

718951401403 is a deficient number, since it is larger than the sum of its proper divisors (1).

718951401403 is an equidigital number, since it uses as much as digits as its factorization.

718951401403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120960, while the sum is 43.

The spelling of 718951401403 in words is "seven hundred eighteen billion, nine hundred fifty-one million, four hundred one thousand, four hundred three".