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72130112121581 is a prime number
BaseRepresentation
bin10000011001101000011001…
…101101011110101011101101
3100110101120102112101020021122
4100121220121231132223231
533423234432200342311
6413224041022510325
721123141263644403
oct2031503155365355
9313346375336248
1072130112121581
1120a8a2329566a8
12810b3707353a5
133132ac043b817
1413b518a649473
1585140a5d30db
hex419a19b5eaed

72130112121581 has 2 divisors, whose sum is σ = 72130112121582. Its totient is φ = 72130112121580.

The previous prime is 72130112121523. The next prime is 72130112121583. The reversal of 72130112121581 is 18512121103127.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 68307481047556 + 3822631074025 = 8264834^2 + 1955155^2 .

It is a cyclic number.

It is not a de Polignac number, because 72130112121581 - 210 = 72130112120557 is a prime.

It is a super-2 number, since 2×721301121215812 (a number of 29 digits) contains 22 as substring.

Together with 72130112121583, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (72130112121583) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 36065056060790 + 36065056060791.

It is an arithmetic number, because the mean of its divisors is an integer number (36065056060791).

Almost surely, 272130112121581 is an apocalyptic number.

It is an amenable number.

72130112121581 is a deficient number, since it is larger than the sum of its proper divisors (1).

72130112121581 is an equidigital number, since it uses as much as digits as its factorization.

72130112121581 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6720, while the sum is 35.

The spelling of 72130112121581 in words is "seventy-two trillion, one hundred thirty billion, one hundred twelve million, one hundred twenty-one thousand, five hundred eighty-one".