Base | Representation |
---|---|
bin | 100010010100001001… |
… | …1010011111100101101 |
3 | 21001012121212002121122 |
4 | 1010220103103330231 |
5 | 2201404243020432 |
6 | 53504125110325 |
7 | 5216056503116 |
oct | 1045023237455 |
9 | 231177762548 |
10 | 73690595117 |
11 | 29285468887 |
12 | 123469b83a5 |
13 | 6c44c27549 |
14 | 37d0c2920d |
15 | 1db461a612 |
hex | 11284d3f2d |
73690595117 has 2 divisors, whose sum is σ = 73690595118. Its totient is φ = 73690595116.
The previous prime is 73690595057. The next prime is 73690595171. The reversal of 73690595117 is 71159509637.
Together with next prime (73690595171) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 59591644996 + 14098950121 = 244114^2 + 118739^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-73690595117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (73690535117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 36845297558 + 36845297559.
It is an arithmetic number, because the mean of its divisors is an integer number (36845297559).
Almost surely, 273690595117 is an apocalyptic number.
It is an amenable number.
73690595117 is a deficient number, since it is larger than the sum of its proper divisors (1).
73690595117 is an equidigital number, since it uses as much as digits as its factorization.
73690595117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1786050, while the sum is 53.
The spelling of 73690595117 in words is "seventy-three billion, six hundred ninety million, five hundred ninety-five thousand, one hundred seventeen".
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