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7550401332119 is a prime number
BaseRepresentation
bin110110111011111011011…
…1111010100001110010111
3222201210220110011122102012
41231313312333110032113
51442201210220111434
624020335000134435
71406332661253032
oct155676677241627
928653813148365
107550401332119
11245111a793628
12a1b39a16741b
13429ccc702b39
141c16271ba019
15d160b0503ce
hex6ddf6fd4397

7550401332119 has 2 divisors, whose sum is σ = 7550401332120. Its totient is φ = 7550401332118.

The previous prime is 7550401332031. The next prime is 7550401332121. The reversal of 7550401332119 is 9112331040557.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 7550401332119 - 236 = 7481681855383 is a prime.

It is a super-2 number, since 2×75504013321192 (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 7550401332121, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (7550401331119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3775200666059 + 3775200666060.

It is an arithmetic number, because the mean of its divisors is an integer number (3775200666060).

Almost surely, 27550401332119 is an apocalyptic number.

7550401332119 is a deficient number, since it is larger than the sum of its proper divisors (1).

7550401332119 is an equidigital number, since it uses as much as digits as its factorization.

7550401332119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 113400, while the sum is 41.

The spelling of 7550401332119 in words is "seven trillion, five hundred fifty billion, four hundred one million, three hundred thirty-two thousand, one hundred nineteen".