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763141321253 is a prime number
BaseRepresentation
bin10110001101011101100…
…01000111001000100101
32200221210122000212010202
423012232301013020211
5100000403134240003
61342325435000245
7106064232126143
oct13065661071045
92627718025122
10763141321253
11274712420923
12103a9a599085
1356c6b95c1ac
1428d1706a593
1514cb74b7088
hexb1aec47225

763141321253 has 2 divisors, whose sum is σ = 763141321254. Its totient is φ = 763141321252.

The previous prime is 763141321207. The next prime is 763141321273. The reversal of 763141321253 is 352123141367.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 732294370564 + 30846950689 = 855742^2 + 175633^2 .

It is an emirp because it is prime and its reverse (352123141367) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-763141321253 is a prime.

It is a super-3 number, since 3×7631413212533 (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (763141321273) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 381570660626 + 381570660627.

It is an arithmetic number, because the mean of its divisors is an integer number (381570660627).

Almost surely, 2763141321253 is an apocalyptic number.

It is an amenable number.

763141321253 is a deficient number, since it is larger than the sum of its proper divisors (1).

763141321253 is an equidigital number, since it uses as much as digits as its factorization.

763141321253 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 90720, while the sum is 38.

The spelling of 763141321253 in words is "seven hundred sixty-three billion, one hundred forty-one million, three hundred twenty-one thousand, two hundred fifty-three".