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7632108778013 is a prime number
BaseRepresentation
bin110111100001111110100…
…1000011111001000011101
31000000121210210010221211222
41233003331020133020131
52000021024321344023
624122050430223125
71415254525141016
oct157037510371035
930017723127758
107632108778013
112482839489015
12a331a1954aa5
134349214c0365
141c5578a1800d
15d37de393cc8
hex6f0fd21f21d

7632108778013 has 2 divisors, whose sum is σ = 7632108778014. Its totient is φ = 7632108778012.

The previous prime is 7632108777973. The next prime is 7632108778027. The reversal of 7632108778013 is 3108778012367.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4356291131929 + 3275817646084 = 2087173^2 + 1809922^2 .

It is an emirp because it is prime and its reverse (3108778012367) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 7632108778013 - 230 = 7631035036189 is a prime.

It is a super-3 number, since 3×76321087780133 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (7632108778033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3816054389006 + 3816054389007.

It is an arithmetic number, because the mean of its divisors is an integer number (3816054389007).

Almost surely, 27632108778013 is an apocalyptic number.

It is an amenable number.

7632108778013 is a deficient number, since it is larger than the sum of its proper divisors (1).

7632108778013 is an equidigital number, since it uses as much as digits as its factorization.

7632108778013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2370816, while the sum is 53.

The spelling of 7632108778013 in words is "seven trillion, six hundred thirty-two billion, one hundred eight million, seven hundred seventy-eight thousand, thirteen".