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766662371024413 is a prime number
BaseRepresentation
bin1010111001010001100111111…
…0010010011001111000011101
310201112112012120211002011010211
42232110121332102121320131
51300441444013440240123
611314315455302332421
7320325346153040563
oct25624317622317035
93645465524064124
10766662371024413
1120231175a661a36
1271ba0378a2a111
1326ba2c4a22a536
14d74692a179a33
155d979aace940d
hex2b9467e499e1d

766662371024413 has 2 divisors, whose sum is σ = 766662371024414. Its totient is φ = 766662371024412.

The previous prime is 766662371024327. The next prime is 766662371024423. The reversal of 766662371024413 is 314420173266667.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 591538913194329 + 175123457830084 = 24321573^2 + 13233422^2 .

It is a cyclic number.

It is not a de Polignac number, because 766662371024413 - 213 = 766662371016221 is a prime.

It is a super-2 number, since 2×7666623710244132 (a number of 31 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (766662371024423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 383331185512206 + 383331185512207.

It is an arithmetic number, because the mean of its divisors is an integer number (383331185512207).

Almost surely, 2766662371024413 is an apocalyptic number.

It is an amenable number.

766662371024413 is a deficient number, since it is larger than the sum of its proper divisors (1).

766662371024413 is an equidigital number, since it uses as much as digits as its factorization.

766662371024413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36578304, while the sum is 58.

The spelling of 766662371024413 in words is "seven hundred sixty-six trillion, six hundred sixty-two billion, three hundred seventy-one million, twenty-four thousand, four hundred thirteen".