Base | Representation |
---|---|
bin | 10001101110110000011111… |
… | …110101011111110111111111 |
3 | 101020002210220111212011200202 |
4 | 101232300133311133313333 |
5 | 40210110424322002223 |
6 | 433503255500114115 |
7 | 22265603053262351 |
oct | 2156603765376777 |
9 | 336083814764622 |
10 | 77979960344063 |
11 | 2293512a754238 |
12 | 88b5056b3593b |
13 | 346862b94a18b |
14 | 15383708590d1 |
15 | 9036874aa428 |
hex | 46ec1fd5fdff |
77979960344063 has 2 divisors, whose sum is σ = 77979960344064. Its totient is φ = 77979960344062.
The previous prime is 77979960344047. The next prime is 77979960344137. The reversal of 77979960344063 is 36044306997977.
It is an a-pointer prime, because the next prime (77979960344137) can be obtained adding 77979960344063 to its sum of digits (74).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 77979960344063 - 24 = 77979960344047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (77979960344003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 38989980172031 + 38989980172032.
It is an arithmetic number, because the mean of its divisors is an integer number (38989980172032).
Almost surely, 277979960344063 is an apocalyptic number.
77979960344063 is a deficient number, since it is larger than the sum of its proper divisors (1).
77979960344063 is an equidigital number, since it uses as much as digits as its factorization.
77979960344063 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296243648, while the sum is 74.
The spelling of 77979960344063 in words is "seventy-seven trillion, nine hundred seventy-nine billion, nine hundred sixty million, three hundred forty-four thousand, sixty-three".
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