Base | Representation |
---|---|
bin | 111001110010011100100… |
… | …1100010001100010101101 |
3 | 1001010021121022100200112101 |
4 | 1303210321030101202231 |
5 | 2020111420114033242 |
6 | 24520400031135101 |
7 | 1446546636343561 |
oct | 163447114214255 |
9 | 31107538320471 |
10 | 7942354049197 |
11 | 2592373893187 |
12 | a83346374491 |
13 | 457c64a845b9 |
14 | 1d65aa6c76a1 |
15 | db8eb20d9b7 |
hex | 739393118ad |
7942354049197 has 2 divisors, whose sum is σ = 7942354049198. Its totient is φ = 7942354049196.
The previous prime is 7942354049101. The next prime is 7942354049219. The reversal of 7942354049197 is 7919404532497.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3999564011881 + 3942790037316 = 1999891^2 + 1985646^2 .
It is a cyclic number.
It is not a de Polignac number, because 7942354049197 - 211 = 7942354047149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (7942354040197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3971177024598 + 3971177024599.
It is an arithmetic number, because the mean of its divisors is an integer number (3971177024599).
Almost surely, 27942354049197 is an apocalyptic number.
It is an amenable number.
7942354049197 is a deficient number, since it is larger than the sum of its proper divisors (1).
7942354049197 is an equidigital number, since it uses as much as digits as its factorization.
7942354049197 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 68584320, while the sum is 64.
The spelling of 7942354049197 in words is "seven trillion, nine hundred forty-two billion, three hundred fifty-four million, forty-nine thousand, one hundred ninety-seven".
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