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799021117441 is a prime number
BaseRepresentation
bin10111010000010010101…
…11101011000000000001
32211101102011012100120001
423220021113223000001
5101042343401224231
61411022031320001
7111504326303011
oct13501127530001
92741364170501
10799021117441
11288954654848
1210aa32680001
135a469224421
142a95c353c41
1515bb73d2b61
hexba095eb001

799021117441 has 2 divisors, whose sum is σ = 799021117442. Its totient is φ = 799021117440.

The previous prime is 799021117439. The next prime is 799021117463. The reversal of 799021117441 is 144711120997.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 773230042225 + 25791075216 = 879335^2 + 160596^2 .

It is an emirp because it is prime and its reverse (144711120997) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 799021117441 - 21 = 799021117439 is a prime.

It is a super-2 number, since 2×7990211174412 (a number of 25 digits) contains 22 as substring.

Together with 799021117439, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 799021117391 and 799021117400.

It is not a weakly prime, because it can be changed into another prime (799021117471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 399510558720 + 399510558721.

It is an arithmetic number, because the mean of its divisors is an integer number (399510558721).

Almost surely, 2799021117441 is an apocalyptic number.

It is an amenable number.

799021117441 is a deficient number, since it is larger than the sum of its proper divisors (1).

799021117441 is an equidigital number, since it uses as much as digits as its factorization.

799021117441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 127008, while the sum is 46.

The spelling of 799021117441 in words is "seven hundred ninety-nine billion, twenty-one million, one hundred seventeen thousand, four hundred forty-one".