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799021117439 is a prime number
BaseRepresentation
bin10111010000010010101…
…11101010111111111111
32211101102011012100112222
423220021113222333333
5101042343401224224
61411022031315555
7111504326303006
oct13501127527777
92741364170488
10799021117439
11288954654846
1210aa3267bbbb
135a46922441c
142a95c353c3d
1515bb73d2b5e
hexba095eafff

799021117439 has 2 divisors, whose sum is σ = 799021117440. Its totient is φ = 799021117438.

The previous prime is 799021117387. The next prime is 799021117441. The reversal of 799021117439 is 934711120997.

It is a strong prime.

It is an emirp because it is prime and its reverse (934711120997) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-799021117439 is a prime.

It is a super-2 number, since 2×7990211174392 (a number of 25 digits) contains 22 as substring.

Together with 799021117441, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (799021111439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 399510558719 + 399510558720.

It is an arithmetic number, because the mean of its divisors is an integer number (399510558720).

Almost surely, 2799021117439 is an apocalyptic number.

799021117439 is a deficient number, since it is larger than the sum of its proper divisors (1).

799021117439 is an equidigital number, since it uses as much as digits as its factorization.

799021117439 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 857304, while the sum is 53.

The spelling of 799021117439 in words is "seven hundred ninety-nine billion, twenty-one million, one hundred seventeen thousand, four hundred thirty-nine".