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800555048131 is a prime number
BaseRepresentation
bin10111010011001001100…
…11001001110011000011
32211112101001120002212211
423221210303021303003
5101104014043020011
61411434145002551
7111560333430106
oct13514463116303
92745331502784
10800555048131
112895714aa663
1210b1a0323457
135a651c66817
142aa65d6a73d
1515c56dd0b21
hexba64cc9cc3

800555048131 has 2 divisors, whose sum is σ = 800555048132. Its totient is φ = 800555048130.

The previous prime is 800555048119. The next prime is 800555048143. The reversal of 800555048131 is 131840555008.

It is a happy number.

800555048131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (800555048119) and next prime (800555048143).

It is a cyclic number.

It is not a de Polignac number, because 800555048131 - 29 = 800555047619 is a prime.

It is a super-2 number, since 2×8005550481312 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (800555048231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 400277524065 + 400277524066.

It is an arithmetic number, because the mean of its divisors is an integer number (400277524066).

Almost surely, 2800555048131 is an apocalyptic number.

800555048131 is a deficient number, since it is larger than the sum of its proper divisors (1).

800555048131 is an equidigital number, since it uses as much as digits as its factorization.

800555048131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96000, while the sum is 40.

The spelling of 800555048131 in words is "eight hundred billion, five hundred fifty-five million, forty-eight thousand, one hundred thirty-one".