Base | Representation |
---|---|
bin | 111010010001111101011… |
… | …1100001101010010101111 |
3 | 1001100202021200221211111012 |
4 | 1310203322330031102233 |
5 | 2022214014424024311 |
6 | 25011431231015435 |
7 | 1454463663122114 |
oct | 164437274152257 |
9 | 31322250854435 |
10 | 8010029126831 |
11 | 2609041691706 |
12 | a9449266a57b |
13 | 46145b63c034 |
14 | 1d998a62490b |
15 | dd55c67878b |
hex | 748faf0d4af |
8010029126831 has 2 divisors, whose sum is σ = 8010029126832. Its totient is φ = 8010029126830.
The previous prime is 8010029126809. The next prime is 8010029126833. The reversal of 8010029126831 is 1386219200108.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 8010029126831 - 230 = 8008955385007 is a prime.
It is a super-2 number, since 2×80100291268312 (a number of 27 digits) contains 22 as substring.
Together with 8010029126833, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (8010029126833) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4005014563415 + 4005014563416.
It is an arithmetic number, because the mean of its divisors is an integer number (4005014563416).
Almost surely, 28010029126831 is an apocalyptic number.
8010029126831 is a deficient number, since it is larger than the sum of its proper divisors (1).
8010029126831 is an equidigital number, since it uses as much as digits as its factorization.
8010029126831 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 41472, while the sum is 41.
The spelling of 8010029126831 in words is "eight trillion, ten billion, twenty-nine million, one hundred twenty-six thousand, eight hundred thirty-one".
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