Base | Representation |
---|---|
bin | 1110111011001001… |
… | …11001001111110101 |
3 | 202200101202021120122 |
4 | 13131210321033311 |
5 | 112402133404301 |
6 | 3403021341325 |
7 | 402361210361 |
oct | 73544711765 |
9 | 22611667518 |
10 | 8012403701 |
11 | 344187a545 |
12 | 1677407845 |
13 | 9a8c96aa3 |
14 | 5601b62a1 |
15 | 31d64a81b |
hex | 1dd9393f5 |
8012403701 has 2 divisors, whose sum is σ = 8012403702. Its totient is φ = 8012403700.
The previous prime is 8012403643. The next prime is 8012403703. The reversal of 8012403701 is 1073042108.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6360062500 + 1652341201 = 79750^2 + 40649^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-8012403701 is a prime.
It is a super-2 number, since 2×80124037012 (a number of 21 digits) contains 22 as substring.
Together with 8012403703, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (8012403703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4006201850 + 4006201851.
It is an arithmetic number, because the mean of its divisors is an integer number (4006201851).
Almost surely, 28012403701 is an apocalyptic number.
It is an amenable number.
8012403701 is a deficient number, since it is larger than the sum of its proper divisors (1).
8012403701 is an equidigital number, since it uses as much as digits as its factorization.
8012403701 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 26.
The square root of 8012403701 is about 89512.0310405255. The cubic root of 8012403701 is about 2001.0331080020.
Adding to 8012403701 its reverse (1073042108), we get a palindrome (9085445809).
The spelling of 8012403701 in words is "eight billion, twelve million, four hundred three thousand, seven hundred one".
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