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80135257093 is a prime number
BaseRepresentation
bin100101010100001101…
…1101111110000000101
321122211202121211211221
41022220123233300011
52303104111211333
6100451424400341
75534553306103
oct1125033576005
9248752554757
1080135257093
1130a92299801
12136451760b1
1377311713b8
143c42b06c73
1521402d9d2d
hex12a86efc05

80135257093 has 2 divisors, whose sum is σ = 80135257094. Its totient is φ = 80135257092.

The previous prime is 80135257091. The next prime is 80135257127. The reversal of 80135257093 is 39075253108.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 71245218724 + 8890038369 = 266918^2 + 94287^2 .

It is a cyclic number.

It is not a de Polignac number, because 80135257093 - 21 = 80135257091 is a prime.

It is a super-2 number, since 2×801352570932 (a number of 23 digits) contains 22 as substring.

Together with 80135257091, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (80135257091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40067628546 + 40067628547.

It is an arithmetic number, because the mean of its divisors is an integer number (40067628547).

Almost surely, 280135257093 is an apocalyptic number.

It is an amenable number.

80135257093 is a deficient number, since it is larger than the sum of its proper divisors (1).

80135257093 is an equidigital number, since it uses as much as digits as its factorization.

80135257093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 226800, while the sum is 43.

The spelling of 80135257093 in words is "eighty billion, one hundred thirty-five million, two hundred fifty-seven thousand, ninety-three".