Base | Representation |
---|---|
bin | 1011011001000011011110010… |
… | …0010110111100001110010011 |
3 | 10220010020120010002200222012222 |
4 | 2312100313210112330032103 |
5 | 1320031433224431131033 |
6 | 11520511343553011255 |
7 | 330562644350464235 |
oct | 26620674426741623 |
9 | 3803216102628188 |
10 | 801603642442643 |
11 | 212463217438857 |
12 | 75aa41a5b53b2b |
13 | 28538b8c512231 |
14 | 101d3b7521a255 |
15 | 62a183c4d8598 |
hex | 2d90de45bc393 |
801603642442643 has 2 divisors, whose sum is σ = 801603642442644. Its totient is φ = 801603642442642.
The previous prime is 801603642442573. The next prime is 801603642442709. The reversal of 801603642442643 is 346244246306108.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 801603642442643 - 246 = 731234898264979 is a prime.
It is not a weakly prime, because it can be changed into another prime (801603642642643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 400801821221321 + 400801821221322.
It is an arithmetic number, because the mean of its divisors is an integer number (400801821221322).
Almost surely, 2801603642442643 is an apocalyptic number.
801603642442643 is a deficient number, since it is larger than the sum of its proper divisors (1).
801603642442643 is an equidigital number, since it uses as much as digits as its factorization.
801603642442643 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15925248, while the sum is 53.
The spelling of 801603642442643 in words is "eight hundred one trillion, six hundred three billion, six hundred forty-two million, four hundred forty-two thousand, six hundred forty-three".
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