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80212416858311 is a prime number
BaseRepresentation
bin10010001111001111101000…
…100111010000100011000111
3101112000020021020122110120112
4102033033220213100203013
541003200012203431221
6442333024155023235
722616104315455413
oct2217175047204307
9345006236573515
1080212416858311
1123615993201811
128bb585413ab1b
13359acc97aa91a
1415b4431ba5d43
1594179802215b
hex48f3e89d08c7

80212416858311 has 2 divisors, whose sum is σ = 80212416858312. Its totient is φ = 80212416858310.

The previous prime is 80212416858241. The next prime is 80212416858313. The reversal of 80212416858311 is 11385861421208.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-80212416858311 is a prime.

Together with 80212416858313, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 80212416858311.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (80212416858313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40106208429155 + 40106208429156.

It is an arithmetic number, because the mean of its divisors is an integer number (40106208429156).

Almost surely, 280212416858311 is an apocalyptic number.

80212416858311 is a deficient number, since it is larger than the sum of its proper divisors (1).

80212416858311 is an equidigital number, since it uses as much as digits as its factorization.

80212416858311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 737280, while the sum is 50.

The spelling of 80212416858311 in words is "eighty trillion, two hundred twelve billion, four hundred sixteen million, eight hundred fifty-eight thousand, three hundred eleven".