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80252558224217 is a prime number
BaseRepresentation
bin10010001111110101000001…
…001110011010101101011001
3101112011001212202201010122022
4102033311001032122231121
541004324214401133332
6442403303303504225
722622025130445621
oct2217650116325531
9345131782633568
1080252558224217
1123630a11a35085
129001597458075
1335a1a25c28142
1415b635d051881
15942847130212
hex48fd4139ab59

80252558224217 has 2 divisors, whose sum is σ = 80252558224218. Its totient is φ = 80252558224216.

The previous prime is 80252558224177. The next prime is 80252558224219. The reversal of 80252558224217 is 71242285525208.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 54647045508496 + 25605512715721 = 7392364^2 + 5060189^2 .

It is a cyclic number.

It is not a de Polignac number, because 80252558224217 - 210 = 80252558223193 is a prime.

Together with 80252558224219, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (80252558224219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40126279112108 + 40126279112109.

It is an arithmetic number, because the mean of its divisors is an integer number (40126279112109).

Almost surely, 280252558224217 is an apocalyptic number.

It is an amenable number.

80252558224217 is a deficient number, since it is larger than the sum of its proper divisors (1).

80252558224217 is an equidigital number, since it uses as much as digits as its factorization.

80252558224217 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7168000, while the sum is 53.

The spelling of 80252558224217 in words is "eighty trillion, two hundred fifty-two billion, five hundred fifty-eight million, two hundred twenty-four thousand, two hundred seventeen".