Base | Representation |
---|---|
bin | 10010010010000101100100… |
… | …100101110001001010001111 |
3 | 101112200220111202202010100022 |
4 | 102102011210211301022033 |
5 | 41014400103203330303 |
6 | 443002453022452355 |
7 | 22636161336101336 |
oct | 2222054445611217 |
9 | 345626452663308 |
10 | 80407770370703 |
11 | 2369082016a006 |
12 | 90276937340bb |
13 | 35b3560284039 |
14 | 15bda84b28d1d |
15 | 9468cd5be438 |
hex | 49216497128f |
80407770370703 has 2 divisors, whose sum is σ = 80407770370704. Its totient is φ = 80407770370702.
The previous prime is 80407770370633. The next prime is 80407770370721. The reversal of 80407770370703 is 30707307770408.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 80407770370703 - 230 = 80406696628879 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (80407770370003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40203885185351 + 40203885185352.
It is an arithmetic number, because the mean of its divisors is an integer number (40203885185352).
Almost surely, 280407770370703 is an apocalyptic number.
80407770370703 is a deficient number, since it is larger than the sum of its proper divisors (1).
80407770370703 is an equidigital number, since it uses as much as digits as its factorization.
80407770370703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4840416, while the sum is 53.
The spelling of 80407770370703 in words is "eighty trillion, four hundred seven billion, seven hundred seventy million, three hundred seventy thousand, seven hundred three".
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