Base | Representation |
---|---|
bin | 1111000111001111… |
… | …10110100100000101 |
3 | 202221110121220100212 |
4 | 13203213312210011 |
5 | 113104120424222 |
6 | 3421043445205 |
7 | 405032344211 |
oct | 74347664405 |
9 | 22843556325 |
10 | 8113842437 |
11 | 3494063a08 |
12 | 16a5386805 |
13 | 9c3cc23cc |
14 | 56d85d941 |
15 | 3274d66e2 |
hex | 1e39f6905 |
8113842437 has 2 divisors, whose sum is σ = 8113842438. Its totient is φ = 8113842436.
The previous prime is 8113842431. The next prime is 8113842439. The reversal of 8113842437 is 7342483118.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8113325476 + 516961 = 90074^2 + 719^2 .
It is a cyclic number.
It is not a de Polignac number, because 8113842437 - 216 = 8113776901 is a prime.
Together with 8113842439, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 8113842394 and 8113842403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (8113842431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4056921218 + 4056921219.
It is an arithmetic number, because the mean of its divisors is an integer number (4056921219).
Almost surely, 28113842437 is an apocalyptic number.
It is an amenable number.
8113842437 is a deficient number, since it is larger than the sum of its proper divisors (1).
8113842437 is an equidigital number, since it uses as much as digits as its factorization.
8113842437 is an evil number, because the sum of its binary digits is even.
The product of its digits is 129024, while the sum is 41.
The square root of 8113842437 is about 90076.8696003586. The cubic root of 8113842437 is about 2009.4422218213.
The spelling of 8113842437 in words is "eight billion, one hundred thirteen million, eight hundred forty-two thousand, four hundred thirty-seven".
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