811471200000 has 432 divisors, whose sum is σ = 2858382989280. Its totient is φ = 203653120000.

The previous prime is 811471199999. The next prime is 811471200011. The reversal of 811471200000 is 2174118.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 40790056 + ... + 40809944.

It is an arithmetic number, because the mean of its divisors is an integer number (6616627290).

Almost surely, 2^811471200000 is an apocalyptic number.

811471200000 is a gapful number since it is divisible by the number (80) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 811471200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1429191494640).

811471200000 is an abundant number, since it is smaller than the sum of its proper divisors (2046911789280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

811471200000 is an equidigital number, since it uses as much as digits as its factorization.

811471200000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19950 (or 19916 counting only the distinct ones).

The product of its (nonzero) digits is 448, while the sum is 24.

Adding to 811471200000 its reverse (2174118), we get a palindrome (811473374118).

The spelling of 811471200000 in words is "eight hundred eleven billion, four hundred seventy-one million, two hundred thousand".