Base | Representation |
---|---|
bin | 10111100111100111110… |
… | …00011110100001010011 |
3 | 2212120202000001221021022 |
4 | 23303303320132201103 |
5 | 101244021123121321 |
6 | 1420452512550055 |
7 | 112426566050546 |
oct | 13636370364123 |
9 | 2776660057238 |
10 | 811545520211 |
11 | 2931a131aa38 |
12 | 111348b5232b |
13 | 5b6b3c0643a |
14 | 2b3c987a85d |
15 | 1619bbdbdab |
hex | bcf3e1e853 |
811545520211 has 2 divisors, whose sum is σ = 811545520212. Its totient is φ = 811545520210.
The previous prime is 811545520169. The next prime is 811545520241. The reversal of 811545520211 is 112025545118.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-811545520211 is a prime.
It is a super-2 number, since 2×8115455202112 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (811545520241) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 405772760105 + 405772760106.
It is an arithmetic number, because the mean of its divisors is an integer number (405772760106).
Almost surely, 2811545520211 is an apocalyptic number.
811545520211 is a deficient number, since it is larger than the sum of its proper divisors (1).
811545520211 is an equidigital number, since it uses as much as digits as its factorization.
811545520211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16000, while the sum is 35.
The spelling of 811545520211 in words is "eight hundred eleven billion, five hundred forty-five million, five hundred twenty thousand, two hundred eleven".
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