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811545520241 is a prime number
BaseRepresentation
bin10111100111100111110…
…00011110100001110001
32212120202000001221022102
423303303320132201301
5101244021123121431
61420452512550145
7112426566050621
oct13636370364161
92776660057272
10811545520241
112931a131aa65
12111348b52355
135b6b3c06461
142b3c987a881
151619bbdbdcb
hexbcf3e1e871

811545520241 has 2 divisors, whose sum is σ = 811545520242. Its totient is φ = 811545520240.

The previous prime is 811545520211. The next prime is 811545520327. The reversal of 811545520241 is 142025545118.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 784145670400 + 27399849841 = 885520^2 + 165529^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-811545520241 is a prime.

It is a super-2 number, since 2×8115455202412 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 811545520195 and 811545520204.

It is not a weakly prime, because it can be changed into another prime (811545520211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 405772760120 + 405772760121.

It is an arithmetic number, because the mean of its divisors is an integer number (405772760121).

Almost surely, 2811545520241 is an apocalyptic number.

It is an amenable number.

811545520241 is a deficient number, since it is larger than the sum of its proper divisors (1).

811545520241 is an equidigital number, since it uses as much as digits as its factorization.

811545520241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64000, while the sum is 38.

The spelling of 811545520241 in words is "eight hundred eleven billion, five hundred forty-five million, five hundred twenty thousand, two hundred forty-one".