Base | Representation |
---|---|
bin | 100101110010111001… |
… | …1111001111001111101 |
3 | 21202111112021012222212 |
4 | 1023211303321321331 |
5 | 2312211220002232 |
6 | 101141531350205 |
7 | 5602226055662 |
oct | 1134563717175 |
9 | 252445235885 |
10 | 81165000317 |
11 | 31470588065 |
12 | 13891bb2365 |
13 | 78665c370b |
14 | 3cdd797a69 |
15 | 21a08e3eb2 |
hex | 12e5cf9e7d |
81165000317 has 2 divisors, whose sum is σ = 81165000318. Its totient is φ = 81165000316.
The previous prime is 81165000283. The next prime is 81165000341. The reversal of 81165000317 is 71300056118.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 78182311321 + 2982688996 = 279611^2 + 54614^2 .
It is a cyclic number.
It is not a de Polignac number, because 81165000317 - 212 = 81164996221 is a prime.
It is a super-2 number, since 2×811650003172 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (81165000377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40582500158 + 40582500159.
It is an arithmetic number, because the mean of its divisors is an integer number (40582500159).
Almost surely, 281165000317 is an apocalyptic number.
It is an amenable number.
81165000317 is a deficient number, since it is larger than the sum of its proper divisors (1).
81165000317 is an equidigital number, since it uses as much as digits as its factorization.
81165000317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5040, while the sum is 32.
The spelling of 81165000317 in words is "eighty-one billion, one hundred sixty-five million, three hundred seventeen", and thus it is an aban number.
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