Base | Representation |
---|---|
bin | 1111000111111100… |
… | …00110110001011101 |
3 | 202221212121021111122 |
4 | 13203332012301131 |
5 | 113112114112442 |
6 | 3421412500325 |
7 | 405133051526 |
oct | 74376066135 |
9 | 22855537448 |
10 | 8119675997 |
11 | 3497388834 |
12 | 16a731a6a5 |
13 | 9c5285714 |
14 | 57053b84d |
15 | 327c89dd2 |
hex | 1e3f86c5d |
8119675997 has 2 divisors, whose sum is σ = 8119675998. Its totient is φ = 8119675996.
The previous prime is 8119675987. The next prime is 8119675999. The reversal of 8119675997 is 7995769118.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7399612441 + 720063556 = 86021^2 + 26834^2 .
It is a cyclic number.
It is not a de Polignac number, because 8119675997 - 24 = 8119675981 is a prime.
Together with 8119675999, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (8119675999) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4059837998 + 4059837999.
It is an arithmetic number, because the mean of its divisors is an integer number (4059837999).
Almost surely, 28119675997 is an apocalyptic number.
It is an amenable number.
8119675997 is a deficient number, since it is larger than the sum of its proper divisors (1).
8119675997 is an equidigital number, since it uses as much as digits as its factorization.
8119675997 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8573040, while the sum is 62.
The square root of 8119675997 is about 90109.2447920856. The cubic root of 8119675997 is about 2009.9236786116.
The spelling of 8119675997 in words is "eight billion, one hundred nineteen million, six hundred seventy-five thousand, nine hundred ninety-seven".
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