Base | Representation |
---|---|
bin | 10111101000011100000… |
… | …01101010001111011101 |
3 | 2212121212120101212211102 |
4 | 23310032001222033131 |
5 | 101300420414311013 |
6 | 1421004222002445 |
7 | 112443503161343 |
oct | 13641601521735 |
9 | 2777776355742 |
10 | 811984135133 |
11 | 2933a696a906 |
12 | 11144ba16425 |
13 | 5b753a47cb2 |
14 | 2b42bc13993 |
15 | 161c547bd58 |
hex | bd0e06a3dd |
811984135133 has 2 divisors, whose sum is σ = 811984135134. Its totient is φ = 811984135132.
The previous prime is 811984135093. The next prime is 811984135159. The reversal of 811984135133 is 331531489118.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 797425782169 + 14558352964 = 892987^2 + 120658^2 .
It is a cyclic number.
It is not a de Polignac number, because 811984135133 - 28 = 811984134877 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (811984135433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 405992067566 + 405992067567.
It is an arithmetic number, because the mean of its divisors is an integer number (405992067567).
Almost surely, 2811984135133 is an apocalyptic number.
It is an amenable number.
811984135133 is a deficient number, since it is larger than the sum of its proper divisors (1).
811984135133 is an equidigital number, since it uses as much as digits as its factorization.
811984135133 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 311040, while the sum is 47.
The spelling of 811984135133 in words is "eight hundred eleven billion, nine hundred eighty-four million, one hundred thirty-five thousand, one hundred thirty-three".
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