8120204431 has 2 divisors, whose sum is σ = 8120204432. Its totient is φ = 8120204430.

The previous prime is 8120204413. The next prime is 8120204437. The reversal of 8120204431 is 1344020218.

Together with previous prime (8120204413) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 8120204431 - 2⁹ = 8120203919 is a prime.

It is a super-2 number, since 2×8120204431² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 8120204396 and 8120204405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (8120204437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4060102215 + 4060102216.

It is an arithmetic number, because the mean of its divisors is an integer number (4060102216).

Almost surely, 2^8120204431 is an apocalyptic number.

8120204431 is a deficient number, since it is larger than the sum of its proper divisors (1).

8120204431 is an equidigital number, since it uses as much as digits as its factorization.

8120204431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 25.

The square root of 8120204431 is about 90112.1769296470. The cubic root of 8120204431 is about 2009.9672800627.

Adding to 8120204431 its reverse (1344020218), we get a palindrome (9464224649).

The spelling of 8120204431 in words is "eight billion, one hundred twenty million, two hundred four thousand, four hundred thirty-one".