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813099854117 is a prime number
BaseRepresentation
bin10111101010100001000…
…01110010100100100101
32212201202022211021112202
423311100201302210211
5101310212030312432
61421311035424245
7112513241503355
oct13652041624445
92781668737482
10813099854117
11293919741011
121117015b5085
135b8a0c40645
142b4d6084b65
151623d3ba462
hexbd50872925

813099854117 has 2 divisors, whose sum is σ = 813099854118. Its totient is φ = 813099854116.

The previous prime is 813099854023. The next prime is 813099854137. The reversal of 813099854117 is 711458990318.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 552069804196 + 261030049921 = 743014^2 + 510911^2 .

It is a cyclic number.

It is not a de Polignac number, because 813099854117 - 212 = 813099850021 is a prime.

It is a super-2 number, since 2×8130998541172 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (813099854137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 406549927058 + 406549927059.

It is an arithmetic number, because the mean of its divisors is an integer number (406549927059).

Almost surely, 2813099854117 is an apocalyptic number.

It is an amenable number.

813099854117 is a deficient number, since it is larger than the sum of its proper divisors (1).

813099854117 is an equidigital number, since it uses as much as digits as its factorization.

813099854117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2177280, while the sum is 56.

The spelling of 813099854117 in words is "eight hundred thirteen billion, ninety-nine million, eight hundred fifty-four thousand, one hundred seventeen".