Base | Representation |
---|---|
bin | 1111001101101111… |
… | …10101101101101011 |
3 | 210002021012221010121 |
4 | 13212313311231223 |
5 | 113212100134112 |
6 | 3430312224111 |
7 | 406263645643 |
oct | 74667655553 |
9 | 23067187117 |
10 | 8168364907 |
11 | 35119134aa |
12 | 16bb69b037 |
13 | a023a2121 |
14 | 576bb3523 |
15 | 32c1a6407 |
hex | 1e6df5b6b |
8168364907 has 2 divisors, whose sum is σ = 8168364908. Its totient is φ = 8168364906.
The previous prime is 8168364863. The next prime is 8168364959. The reversal of 8168364907 is 7094638618.
It is a happy number.
8168364907 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is an a-pointer prime, because the next prime (8168364959) can be obtained adding 8168364907 to its sum of digits (52).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 8168364907 - 219 = 8167840619 is a prime.
It is not a weakly prime, because it can be changed into another prime (8168314907) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4084182453 + 4084182454.
It is an arithmetic number, because the mean of its divisors is an integer number (4084182454).
Almost surely, 28168364907 is an apocalyptic number.
8168364907 is a deficient number, since it is larger than the sum of its proper divisors (1).
8168364907 is an equidigital number, since it uses as much as digits as its factorization.
8168364907 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1741824, while the sum is 52.
The square root of 8168364907 is about 90379.0070038391. The cubic root of 8168364907 is about 2013.9331176282.
The spelling of 8168364907 in words is "eight billion, one hundred sixty-eight million, three hundred sixty-four thousand, nine hundred seven".
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