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82544251331 is a prime number
BaseRepresentation
bin100110011100000000…
…1010101000111000011
321220001122120102200202
41030320001111013003
52323022312020311
6101530441435415
75651344362653
oct1147001250703
9256048512622
1082544251331
1132009094833
1213bb7a9bb6b
137a26288b89
143dd0a28363
152231a3ae3b
hex13380551c3

82544251331 has 2 divisors, whose sum is σ = 82544251332. Its totient is φ = 82544251330.

The previous prime is 82544251291. The next prime is 82544251333. The reversal of 82544251331 is 13315244528.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 82544251331 - 210 = 82544250307 is a prime.

It is a super-2 number, since 2×825442513312 (a number of 23 digits) contains 22 as substring.

Together with 82544251333, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (82544251333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41272125665 + 41272125666.

It is an arithmetic number, because the mean of its divisors is an integer number (41272125666).

Almost surely, 282544251331 is an apocalyptic number.

82544251331 is a deficient number, since it is larger than the sum of its proper divisors (1).

82544251331 is an equidigital number, since it uses as much as digits as its factorization.

82544251331 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 115200, while the sum is 38.

Adding to 82544251331 its reverse (13315244528), we get a palindrome (95859495859).

The spelling of 82544251331 in words is "eighty-two billion, five hundred forty-four million, two hundred fifty-one thousand, three hundred thirty-one".