Base | Representation |
---|---|
bin | 100110011100000000… |
… | …1010101000111000011 |
3 | 21220001122120102200202 |
4 | 1030320001111013003 |
5 | 2323022312020311 |
6 | 101530441435415 |
7 | 5651344362653 |
oct | 1147001250703 |
9 | 256048512622 |
10 | 82544251331 |
11 | 32009094833 |
12 | 13bb7a9bb6b |
13 | 7a26288b89 |
14 | 3dd0a28363 |
15 | 2231a3ae3b |
hex | 13380551c3 |
82544251331 has 2 divisors, whose sum is σ = 82544251332. Its totient is φ = 82544251330.
The previous prime is 82544251291. The next prime is 82544251333. The reversal of 82544251331 is 13315244528.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 82544251331 - 210 = 82544250307 is a prime.
It is a super-2 number, since 2×825442513312 (a number of 23 digits) contains 22 as substring.
Together with 82544251333, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (82544251333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41272125665 + 41272125666.
It is an arithmetic number, because the mean of its divisors is an integer number (41272125666).
Almost surely, 282544251331 is an apocalyptic number.
82544251331 is a deficient number, since it is larger than the sum of its proper divisors (1).
82544251331 is an equidigital number, since it uses as much as digits as its factorization.
82544251331 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 115200, while the sum is 38.
Adding to 82544251331 its reverse (13315244528), we get a palindrome (95859495859).
The spelling of 82544251331 in words is "eighty-two billion, five hundred forty-four million, two hundred fifty-one thousand, three hundred thirty-one".
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