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831494004053903 is a prime number
BaseRepresentation
bin1011110100001111010100100…
…0101111101001011110001111
311001001002001100210102111201122
42331003311020233221132033
51332441144210014211103
612104235023325031155
7340066313362230311
oct27503651057513617
94031061323374648
10831494004053903
11220a37699314683
12793111376b54bb
13298c6718344838
141094874b4337b1
15661e101ce8b38
hex2f43d48be978f

831494004053903 has 2 divisors, whose sum is σ = 831494004053904. Its totient is φ = 831494004053902.

The previous prime is 831494004053893. The next prime is 831494004054011. The reversal of 831494004053903 is 309350400494138.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 831494004053903 - 210 = 831494004052879 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (831494004053003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 415747002026951 + 415747002026952.

It is an arithmetic number, because the mean of its divisors is an integer number (415747002026952).

Almost surely, 2831494004053903 is an apocalyptic number.

831494004053903 is a deficient number, since it is larger than the sum of its proper divisors (1).

831494004053903 is an equidigital number, since it uses as much as digits as its factorization.

831494004053903 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5598720, while the sum is 53.

The spelling of 831494004053903 in words is "eight hundred thirty-one trillion, four hundred ninety-four billion, four million, fifty-three thousand, nine hundred three".