Search a number
-
+
832026995981 is a prime number
BaseRepresentation
bin11000001101110001010…
…11000110110100001101
32221112121101120201002222
430012320223012310031
5102112442402332411
61434121122025125
7114053255530106
oct14067053066415
92845541521088
10832026995981
112a0951603915
121153041a81a5
13605c927b67c
142c3ada953ad
1516999d624db
hexc1b8ac6d0d

832026995981 has 2 divisors, whose sum is σ = 832026995982. Its totient is φ = 832026995980.

The previous prime is 832026995971. The next prime is 832026995983. The reversal of 832026995981 is 189599620238.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 616484077225 + 215542918756 = 785165^2 + 464266^2 .

It is a cyclic number.

It is not a de Polignac number, because 832026995981 - 226 = 831959887117 is a prime.

It is a super-2 number, since 2×8320269959812 (a number of 25 digits) contains 22 as substring.

Together with 832026995983, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (832026995983) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 416013497990 + 416013497991.

It is an arithmetic number, because the mean of its divisors is an integer number (416013497991).

Almost surely, 2832026995981 is an apocalyptic number.

It is an amenable number.

832026995981 is a deficient number, since it is larger than the sum of its proper divisors (1).

832026995981 is an equidigital number, since it uses as much as digits as its factorization.

832026995981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16796160, while the sum is 62.

The spelling of 832026995981 in words is "eight hundred thirty-two billion, twenty-six million, nine hundred ninety-five thousand, nine hundred eighty-one".