Base | Representation |
---|---|
bin | 10011010100111110011001… |
… | …100000010001010011100111 |
3 | 102010222022212221121120121022 |
4 | 103110332121200101103213 |
5 | 42120202222410104204 |
6 | 500442231325041355 |
7 | 23622233062640552 |
oct | 2324763140212347 |
9 | 363868787546538 |
10 | 85004273128679 |
11 | 250a3123140503 |
12 | 964a4930b625b |
13 | 3857b3a2c7a98 |
14 | 16dc32ba6b699 |
15 | 9c62523825be |
hex | 4d4f998114e7 |
85004273128679 has 2 divisors, whose sum is σ = 85004273128680. Its totient is φ = 85004273128678.
The previous prime is 85004273128543. The next prime is 85004273128681. The reversal of 85004273128679 is 97682137240058.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 85004273128679 - 212 = 85004273124583 is a prime.
Together with 85004273128681, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (85004276128679) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 42502136564339 + 42502136564340.
It is an arithmetic number, because the mean of its divisors is an integer number (42502136564340).
It is a 1-persistent number, because it is pandigital, but 2⋅85004273128679 = 170008546257358 is not.
Almost surely, 285004273128679 is an apocalyptic number.
85004273128679 is a deficient number, since it is larger than the sum of its proper divisors (1).
85004273128679 is an equidigital number, since it uses as much as digits as its factorization.
85004273128679 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40642560, while the sum is 62.
The spelling of 85004273128679 in words is "eighty-five trillion, four billion, two hundred seventy-three million, one hundred twenty-eight thousand, six hundred seventy-nine".
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