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85100926853 is a prime number
BaseRepresentation
bin100111101000001101…
…0010001011110000101
322010122211102000011202
41033100122101132011
52343241314124403
6103032252112245
76101610641315
oct1172032213605
9263584360152
1085100926853
1133100288a08
12145b0165685
138042b70027
1441943cd445
15233120e688
hex13d0691785

85100926853 has 2 divisors, whose sum is σ = 85100926854. Its totient is φ = 85100926852.

The previous prime is 85100926819. The next prime is 85100926879. The reversal of 85100926853 is 35862900158.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 72718133569 + 12382793284 = 269663^2 + 111278^2 .

It is a cyclic number.

It is not a de Polignac number, because 85100926853 - 222 = 85096732549 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 85100926798 and 85100926807.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (85100926153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 42550463426 + 42550463427.

It is an arithmetic number, because the mean of its divisors is an integer number (42550463427).

Almost surely, 285100926853 is an apocalyptic number.

It is an amenable number.

85100926853 is a deficient number, since it is larger than the sum of its proper divisors (1).

85100926853 is an equidigital number, since it uses as much as digits as its factorization.

85100926853 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 518400, while the sum is 47.

The spelling of 85100926853 in words is "eighty-five billion, one hundred million, nine hundred twenty-six thousand, eight hundred fifty-three".