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851458335041 is a prime number
BaseRepresentation
bin11000110001111101101…
…11110010000101000001
310000101202121002000012102
430120332313302011001
5102422241313210131
61451053215040145
7115341634301306
oct14307667620501
93011677060172
10851458335041
112a911303a516
12119027810055
13623a4bb1032
142d2d46310ad
1517235c011cb
hexc63edf2141

851458335041 has 2 divisors, whose sum is σ = 851458335042. Its totient is φ = 851458335040.

The previous prime is 851458335023. The next prime is 851458335043. The reversal of 851458335041 is 140533854158.

851458335041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 851458335025 + 16 = 922745^2 + 4^2 .

It is a cyclic number.

It is not a de Polignac number, because 851458335041 - 230 = 850384593217 is a prime.

Together with 851458335043, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (851458335043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 425729167520 + 425729167521.

It is an arithmetic number, because the mean of its divisors is an integer number (425729167521).

Almost surely, 2851458335041 is an apocalyptic number.

It is an amenable number.

851458335041 is a deficient number, since it is larger than the sum of its proper divisors (1).

851458335041 is an equidigital number, since it uses as much as digits as its factorization.

851458335041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152000, while the sum is 47.

The spelling of 851458335041 in words is "eight hundred fifty-one billion, four hundred fifty-eight million, three hundred thirty-five thousand, forty-one".