Base | Representation |
---|---|
bin | 100111101011000011… |
… | …0100010011110110111 |
3 | 22010220111002101222001 |
4 | 1033112012202132313 |
5 | 2343440240320301 |
6 | 103045542520131 |
7 | 6104150411152 |
oct | 1172606423667 |
9 | 263814071861 |
10 | 85196416951 |
11 | 3314a17a048 |
12 | 14618136047 |
13 | 8059894b49 |
14 | 41a2d68c99 |
15 | 23397c2c01 |
hex | 13d61a27b7 |
85196416951 has 2 divisors, whose sum is σ = 85196416952. Its totient is φ = 85196416950.
The previous prime is 85196416889. The next prime is 85196416967. The reversal of 85196416951 is 15961469158.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 85196416951 - 217 = 85196285879 is a prime.
It is a super-2 number, since 2×851964169512 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 85196416892 and 85196416901.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (85196419951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 42598208475 + 42598208476.
It is an arithmetic number, because the mean of its divisors is an integer number (42598208476).
Almost surely, 285196416951 is an apocalyptic number.
85196416951 is a deficient number, since it is larger than the sum of its proper divisors (1).
85196416951 is an equidigital number, since it uses as much as digits as its factorization.
85196416951 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2332800, while the sum is 55.
The spelling of 85196416951 in words is "eighty-five billion, one hundred ninety-six million, four hundred sixteen thousand, nine hundred fifty-one".
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