Base | Representation |
---|---|
bin | 111110110111000010100… |
… | …1001111101011000011101 |
3 | 1010120220211120011010000002 |
4 | 1331232011021331120131 |
5 | 2113022004240301301 |
6 | 30212520332144045 |
7 | 1551114466436015 |
oct | 175560511753035 |
9 | 33526746133002 |
10 | 8639413212701 |
11 | 2830a55590897 |
12 | b76462008025 |
13 | 4a8901b832ab |
14 | 21c2151c6c45 |
15 | eeae700c16b |
hex | 7db8527d61d |
8639413212701 has 2 divisors, whose sum is σ = 8639413212702. Its totient is φ = 8639413212700.
The previous prime is 8639413212667. The next prime is 8639413212713. The reversal of 8639413212701 is 1072123149368.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4612572336100 + 4026840876601 = 2147690^2 + 2006699^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-8639413212701 is a prime.
It is a super-2 number, since 2×86394132127012 (a number of 27 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (8639413292701) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4319706606350 + 4319706606351.
It is an arithmetic number, because the mean of its divisors is an integer number (4319706606351).
Almost surely, 28639413212701 is an apocalyptic number.
It is an amenable number.
8639413212701 is a deficient number, since it is larger than the sum of its proper divisors (1).
8639413212701 is an equidigital number, since it uses as much as digits as its factorization.
8639413212701 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 435456, while the sum is 47.
The spelling of 8639413212701 in words is "eight trillion, six hundred thirty-nine billion, four hundred thirteen million, two hundred twelve thousand, seven hundred one".
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