Base | Representation |
---|---|
bin | 101000001111000011… |
… | …1110100001110100011 |
3 | 22021000200201010020202 |
4 | 1100132013310032203 |
5 | 2403424101230311 |
6 | 103405504455415 |
7 | 6146121633251 |
oct | 1203607641643 |
9 | 267020633222 |
10 | 86404711331 |
11 | 3370a230544 |
12 | 148b491a56b |
13 | 81c0001733 |
14 | 42796175d1 |
15 | 23aa8eae3b |
hex | 141e1f43a3 |
86404711331 has 2 divisors, whose sum is σ = 86404711332. Its totient is φ = 86404711330.
The previous prime is 86404711321. The next prime is 86404711333. The reversal of 86404711331 is 13311740468.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 86404711331 - 210 = 86404710307 is a prime.
It is a super-2 number, since 2×864047113312 (a number of 23 digits) contains 22 as substring.
It is a Sophie Germain prime.
Together with 86404711333, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (86404711333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 43202355665 + 43202355666.
It is an arithmetic number, because the mean of its divisors is an integer number (43202355666).
Almost surely, 286404711331 is an apocalyptic number.
86404711331 is a deficient number, since it is larger than the sum of its proper divisors (1).
86404711331 is an equidigital number, since it uses as much as digits as its factorization.
86404711331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48384, while the sum is 38.
The spelling of 86404711331 in words is "eighty-six billion, four hundred four million, seven hundred eleven thousand, three hundred thirty-one".
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