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86812507493 is a prime number
BaseRepresentation
bin101000011011001101…
…1011011110101100101
322022002010001022102022
41100312123123311211
52410243000214433
6103514153152525
76162203065325
oct1206633336545
9268063038368
1086812507493
11338a9440868
12149a93bb745
13825664273a
1442b784b285
1523d15ee698
hex14366dbd65

86812507493 has 2 divisors, whose sum is σ = 86812507494. Its totient is φ = 86812507492.

The previous prime is 86812507459. The next prime is 86812507531. The reversal of 86812507493 is 39470521868.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 77176729249 + 9635778244 = 277807^2 + 98162^2 .

It is a cyclic number.

It is not a de Polignac number, because 86812507493 - 28 = 86812507237 is a prime.

It is a super-2 number, since 2×868125074932 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (86812527493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 43406253746 + 43406253747.

It is an arithmetic number, because the mean of its divisors is an integer number (43406253747).

It is a 2-persistent number, because it is pandigital, and so is 2⋅86812507493 = 173625014986, but 3⋅86812507493 = 260437522479 is not.

Almost surely, 286812507493 is an apocalyptic number.

It is an amenable number.

86812507493 is a deficient number, since it is larger than the sum of its proper divisors (1).

86812507493 is an equidigital number, since it uses as much as digits as its factorization.

86812507493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2903040, while the sum is 53.

The spelling of 86812507493 in words is "eighty-six billion, eight hundred twelve million, five hundred seven thousand, four hundred ninety-three".