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91022012402513 is a prime number
BaseRepresentation
bin10100101100100010110110…
…101101110100101101010001
3102221021121201112201121110112
4110230202312231310231101
543412301040133340023
6521330534002211105
725113060214536413
oct2454426655645521
9387247645647415
1091022012402513
1127003245075945
12a260813953a95
133ba345385b4ca
1418696bb7b89b3
15a7ca58871478
hex52c8b6b74b51

91022012402513 has 2 divisors, whose sum is σ = 91022012402514. Its totient is φ = 91022012402512.

The previous prime is 91022012402443. The next prime is 91022012402557. The reversal of 91022012402513 is 31520421022019.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 91018144557649 + 3867844864 = 9540343^2 + 62192^2 .

It is an emirp because it is prime and its reverse (31520421022019) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 91022012402513 - 216 = 91022012336977 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 91022012402513.

It is not a weakly prime, because it can be changed into another prime (91022012402413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 45511006201256 + 45511006201257.

It is an arithmetic number, because the mean of its divisors is an integer number (45511006201257).

Almost surely, 291022012402513 is an apocalyptic number.

It is an amenable number.

91022012402513 is a deficient number, since it is larger than the sum of its proper divisors (1).

91022012402513 is an equidigital number, since it uses as much as digits as its factorization.

91022012402513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8640, while the sum is 32.

The spelling of 91022012402513 in words is "ninety-one trillion, twenty-two billion, twelve million, four hundred two thousand, five hundred thirteen".