Base | Representation |
---|---|
bin | 1110010101010111010110… |
… | …11111111000100101000011 |
3 | 11010121022201100002022002112 |
4 | 13022223223133320211003 |
5 | 13112412310240201034 |
6 | 151012140450205535 |
7 | 6432163263010136 |
oct | 712535337704503 |
9 | 133538640068075 |
10 | 31520421022019 |
11 | a05280aa27546 |
12 | 3650a512838ab |
13 | 1478494522427 |
14 | 7ad84cbb621d |
15 | 399db9d567ce |
hex | 1caaeb7f8943 |
31520421022019 has 2 divisors, whose sum is σ = 31520421022020. Its totient is φ = 31520421022018.
The previous prime is 31520421021997. The next prime is 31520421022021. The reversal of 31520421022019 is 91022012402513.
It is a strong prime.
It is an emirp because it is prime and its reverse (91022012402513) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31520421022019 - 216 = 31520420956483 is a prime.
It is a super-2 number, since 2×315204210220192 (a number of 28 digits) contains 22 as substring.
Together with 31520421022021, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (31520420022019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15760210511009 + 15760210511010.
It is an arithmetic number, because the mean of its divisors is an integer number (15760210511010).
Almost surely, 231520421022019 is an apocalyptic number.
31520421022019 is a deficient number, since it is larger than the sum of its proper divisors (1).
31520421022019 is an equidigital number, since it uses as much as digits as its factorization.
31520421022019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 32.
The spelling of 31520421022019 in words is "thirty-one trillion, five hundred twenty billion, four hundred twenty-one million, twenty-two thousand, nineteen".
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