Base | Representation |
---|---|
bin | 10100101111111011110110… |
… | …010001101000011001000111 |
3 | 102222002220010100010220010222 |
4 | 110233323312101220121013 |
5 | 43430110223242102342 |
6 | 522025545500534555 |
7 | 25135646100043643 |
oct | 2457736621503107 |
9 | 388086110126128 |
10 | 91255006987847 |
11 | 2709303848238a |
12 | a2999b925145b |
13 | 3bbc40577c551 |
14 | 1876aa18dbc23 |
15 | a83b43793ed2 |
hex | 52fef6468647 |
91255006987847 has 2 divisors, whose sum is σ = 91255006987848. Its totient is φ = 91255006987846.
The previous prime is 91255006987813. The next prime is 91255006987849. The reversal of 91255006987847 is 74878960055219.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 91255006987847 - 26 = 91255006987783 is a prime.
Together with 91255006987849, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (91255006987849) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 45627503493923 + 45627503493924.
It is an arithmetic number, because the mean of its divisors is an integer number (45627503493924).
Almost surely, 291255006987847 is an apocalyptic number.
91255006987847 is a deficient number, since it is larger than the sum of its proper divisors (1).
91255006987847 is an equidigital number, since it uses as much as digits as its factorization.
91255006987847 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 304819200, while the sum is 71.
The spelling of 91255006987847 in words is "ninety-one trillion, two hundred fifty-five billion, six million, nine hundred eighty-seven thousand, eight hundred forty-seven".
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