Base | Representation |
---|---|
bin | 11010100101100110001… |
… | …11101010010000010111 |
3 | 10020100000001021201111122 |
4 | 31102303013222100113 |
5 | 104431411234242003 |
6 | 1535401301554155 |
7 | 123000220356122 |
oct | 15226307522027 |
9 | 3210001251448 |
10 | 913538196503 |
11 | 32247a550249 |
12 | 12907211595b |
13 | 681b94c787a |
14 | 3230340b3b9 |
15 | 18b6ad3e238 |
hex | d4b31ea417 |
913538196503 has 2 divisors, whose sum is σ = 913538196504. Its totient is φ = 913538196502.
The previous prime is 913538196421. The next prime is 913538196517. The reversal of 913538196503 is 305691835319.
913538196503 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-913538196503 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (913538196553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 456769098251 + 456769098252.
It is an arithmetic number, because the mean of its divisors is an integer number (456769098252).
Almost surely, 2913538196503 is an apocalyptic number.
913538196503 is a deficient number, since it is larger than the sum of its proper divisors (1).
913538196503 is an equidigital number, since it uses as much as digits as its factorization.
913538196503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2624400, while the sum is 53.
The spelling of 913538196503 in words is "nine hundred thirteen billion, five hundred thirty-eight million, one hundred ninety-six thousand, five hundred three".
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