Base | Representation |
---|---|
bin | 10100110010011011001101… |
… | …010011000110001010001111 |
3 | 102222201020210101001222220021 |
4 | 110302123031103012022033 |
5 | 43440411142224313103 |
6 | 522240325012003011 |
7 | 25154214303244366 |
oct | 2462331523061217 |
9 | 388636711058807 |
10 | 91426118197903 |
11 | 27149665281075 |
12 | a306bb2000467 |
13 | 3c025a49b0878 |
14 | 1881094d907dd |
15 | a8830a93bbbd |
hex | 5326cd4c628f |
91426118197903 has 2 divisors, whose sum is σ = 91426118197904. Its totient is φ = 91426118197902.
The previous prime is 91426118197879. The next prime is 91426118197927. The reversal of 91426118197903 is 30979181162419.
It is a balanced prime because it is at equal distance from previous prime (91426118197879) and next prime (91426118197927).
It is a cyclic number.
It is not a de Polignac number, because 91426118197903 - 213 = 91426118189711 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (91426118197993) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 45713059098951 + 45713059098952.
It is an arithmetic number, because the mean of its divisors is an integer number (45713059098952).
Almost surely, 291426118197903 is an apocalyptic number.
91426118197903 is a deficient number, since it is larger than the sum of its proper divisors (1).
91426118197903 is an equidigital number, since it uses as much as digits as its factorization.
91426118197903 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5878656, while the sum is 61.
The spelling of 91426118197903 in words is "ninety-one trillion, four hundred twenty-six billion, one hundred eighteen million, one hundred ninety-seven thousand, nine hundred three".
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