Base | Representation |
---|---|
bin | 101010101100110010… |
… | …1001111111100010011 |
3 | 22202200112112221111221 |
4 | 1111121211033330103 |
5 | 3000243444000232 |
6 | 110043010145511 |
7 | 6424225523323 |
oct | 1253145177423 |
9 | 282615487457 |
10 | 91697250067 |
11 | 359857861a5 |
12 | 15931282297 |
13 | 8854647c67 |
14 | 461c4a9283 |
15 | 25ba38a897 |
hex | 155994ff13 |
91697250067 has 2 divisors, whose sum is σ = 91697250068. Its totient is φ = 91697250066.
The previous prime is 91697250059. The next prime is 91697250119. The reversal of 91697250067 is 76005279619.
It is a happy number.
It is an a-pointer prime, because the next prime (91697250119) can be obtained adding 91697250067 to its sum of digits (52).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 91697250067 - 23 = 91697250059 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 91697249996 and 91697250023.
It is not a weakly prime, because it can be changed into another prime (91697250167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 45848625033 + 45848625034.
It is an arithmetic number, because the mean of its divisors is an integer number (45848625034).
Almost surely, 291697250067 is an apocalyptic number.
91697250067 is a deficient number, since it is larger than the sum of its proper divisors (1).
91697250067 is an equidigital number, since it uses as much as digits as its factorization.
91697250067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1428840, while the sum is 52.
The spelling of 91697250067 in words is "ninety-one billion, six hundred ninety-seven million, two hundred fifty thousand, sixty-seven".
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