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939492540053 is a prime number
BaseRepresentation
bin11011010101111100001…
…11100111111010010101
310022210222211221222112222
431222332013213322111
5110343040042240203
61555332533352125
7124606333554164
oct15527607477225
93283884858488
10939492540053
11332489056751
121320b6198645
136a794673bc2
14336864193db
15196896c5038
hexdabe1e7e95

939492540053 has 2 divisors, whose sum is σ = 939492540054. Its totient is φ = 939492540052.

The previous prime is 939492540023. The next prime is 939492540061. The reversal of 939492540053 is 350045294939.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 746207451889 + 193285088164 = 863833^2 + 439642^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-939492540053 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 939492539977 and 939492540004.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (939492540023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 469746270026 + 469746270027.

It is an arithmetic number, because the mean of its divisors is an integer number (469746270027).

Almost surely, 2939492540053 is an apocalyptic number.

It is an amenable number.

939492540053 is a deficient number, since it is larger than the sum of its proper divisors (1).

939492540053 is an equidigital number, since it uses as much as digits as its factorization.

939492540053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5248800, while the sum is 53.

The spelling of 939492540053 in words is "nine hundred thirty-nine billion, four hundred ninety-two million, five hundred forty thousand, fifty-three".