Base | Representation |
---|---|
bin | 1011001111001… |
… | …10101100101001 |
3 | 20120101022122212 |
4 | 11213212230221 |
5 | 143113040301 |
6 | 13204254505 |
7 | 2223160256 |
oct | 547465451 |
9 | 216338585 |
10 | 94268201 |
11 | 49237105 |
12 | 276a1435 |
13 | 166b7901 |
14 | c73c42d |
15 | 84214bb |
hex | 59e6b29 |
94268201 has 2 divisors, whose sum is σ = 94268202. Its totient is φ = 94268200.
The previous prime is 94268137. The next prime is 94268203. The reversal of 94268201 is 10286249.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 87403801 + 6864400 = 9349^2 + 2620^2 .
It is an emirp because it is prime and its reverse (10286249) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 94268201 - 26 = 94268137 is a prime.
It is a super-3 number, since 3×942682013 (a number of 25 digits) contains 333 as substring.
Together with 94268203, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (94268203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47134100 + 47134101.
It is an arithmetic number, because the mean of its divisors is an integer number (47134101).
Almost surely, 294268201 is an apocalyptic number.
It is an amenable number.
94268201 is a deficient number, since it is larger than the sum of its proper divisors (1).
94268201 is an equidigital number, since it uses as much as digits as its factorization.
94268201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 32.
The square root of 94268201 is about 9709.1812734133. The cubic root of 94268201 is about 455.1156184867.
The spelling of 94268201 in words is "ninety-four million, two hundred sixty-eight thousand, two hundred one".
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