Base | Representation |
---|---|
bin | 101100010000011011… |
… | …1110000100100110111 |
3 | 100002022112222021021222 |
4 | 1120200313300210313 |
5 | 3024120414041221 |
6 | 111354445300555 |
7 | 6603125126036 |
oct | 1304067604467 |
9 | 302275867258 |
10 | 95040768311 |
11 | 37341043a15 |
12 | 16504b6475b |
13 | 8c68256318 |
14 | 485857271d |
15 | 2713b879ab |
hex | 1620df0937 |
95040768311 has 2 divisors, whose sum is σ = 95040768312. Its totient is φ = 95040768310.
The previous prime is 95040768307. The next prime is 95040768313. The reversal of 95040768311 is 11386704059.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 95040768311 - 22 = 95040768307 is a prime.
It is a super-2 number, since 2×950407683112 (a number of 23 digits) contains 22 as substring.
Together with 95040768313, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (95040768313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47520384155 + 47520384156.
It is an arithmetic number, because the mean of its divisors is an integer number (47520384156).
Almost surely, 295040768311 is an apocalyptic number.
95040768311 is a deficient number, since it is larger than the sum of its proper divisors (1).
95040768311 is an equidigital number, since it uses as much as digits as its factorization.
95040768311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 181440, while the sum is 44.
The spelling of 95040768311 in words is "ninety-five billion, forty million, seven hundred sixty-eight thousand, three hundred eleven".
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